The electric field of a plane electromagnetic wave is given by $\vec E = {E_0}\hat i\,\cos \,\left( {kz} \right)\,\cos \,\left( {\omega t} \right)$ The corresponding magnetic field $\vec B$ is then given by
$\vec B = \frac{{{E_0}}}{C}\hat j\,\sin \,\left( {kz} \right)\,\cos \,\left( {\omega t} \right)$
$\vec B = \frac{{{E_0}}}{C}\hat k\,\sin \,\left( {kz} \right)\,\cos \,\left( {\omega t} \right)$
$\vec B = \frac{{{E_0}}}{C}\hat j\,\cos \,\left( {kz} \right)\,\sin \,\left( {\omega t} \right)$
$\vec B = \frac{{{E_0}}}{C}\hat j\,\sin \,\left( {kz} \right)\,\sin \,\left( {\omega t} \right)$
In an $EMW$ phase difference between electric and magnetic field vectors $\vec E$ and $\vec B$ is
In an electromagnetic wave, the amplitude of electric field is $1 V/m.$ the frequency of wave is $5 \times {10^{14}}\,Hz$. The wave is propagating along $z-$ axis. The average energy density of electric field, in $Joule/m^3$, will be
During the propagation of electromagnetic waves in a medium
A plane electromagnetic wave of frequency $28 \,MHz$ travels in free space along the positive $x$-direction. At a particular point in space and time, electric field is $9.3 \,V / m$ along positive $y$-direction. The magnetic field (in $T$ ) at that point is
In an electromagnetic wave, at an instant and at a particular position, the electric field is along the negative $z$-axis and magnetic field is along the positive $x$-axis. Then the direction of propagation of electromagnetic wave is