The electric field of a plane electromagnetic wave is given by $\vec E = {E_0}\hat i\,\cos \,\left( {kz} \right)\,\cos \,\left( {\omega t} \right)$ The corresponding magnetic field $\vec B$ is then given by

  • [JEE MAIN 2019]
  • A

    $\vec B = \frac{{{E_0}}}{C}\hat j\,\sin \,\left( {kz} \right)\,\cos \,\left( {\omega t} \right)$

  • B

    $\vec B = \frac{{{E_0}}}{C}\hat k\,\sin \,\left( {kz} \right)\,\cos \,\left( {\omega t} \right)$

  • C

    $\vec B = \frac{{{E_0}}}{C}\hat j\,\cos \,\left( {kz} \right)\,\sin \,\left( {\omega t} \right)$

  • D

    $\vec B = \frac{{{E_0}}}{C}\hat j\,\sin \,\left( {kz} \right)\,\sin \,\left( {\omega t} \right)$

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